0=-5t^2+15t-22

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Solution for 0=-5t^2+15t-22 equation: 



0=-5t^2+15t-22

We move all terms to the left:

0-(-5t^2+15t-22)=0

We add all the numbers together, and all the variables

-(-5t^2+15t-22)=0

We get rid of parentheses

5t^2-15t+22=0

a = 5; b = -15; c = +22;
Δ = b2-4ac
Δ = -152-4·5·22
Δ = -215
Delta is less than zero, so there is no solution for the equation

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